Solution : In D RPQ = 80 + = 90 TP PQ TPQ = 90 + =90 = 90 From eq. In the given figure, RQ and TP are perpendicular to PQ, also TS PR prove that ST.RQ = PS.PQ. (iv) AC + DE = AB +BC + BD + BE = AB + BE + BC + BD AC +DE = AE + CD Hence Proved. To prove : AC + DE = AE + CD In ABC by using Pythagoras theorem, AC = AB + BC.(i) In ABE by using Pythagoras theorem AE = AB + BE.(ii) In BCD by Pythagoras theorem CD = BD +BC.(iii) In DBE by Pythagoras theorem DE = DB + BE.(iv) Adding eq. Solution : In ABC, B = 60 and D, E are point of AB, BC respectively. D and E are any point on AB and BC respectively. ABC is a right angled triangle in which B = 90. (ii) u 4v = u + v = 9 7v = 7 v = Putting the value of v in eq. Solve the following pair of equations by reducing them to a pair of linear equations : 4 - = x y + x y = 9 4 Solution : Given, x y = Let + x y = 9 x = u, = v y So, u 4v =.(i) u + v = 9.(ii) On solving eq. 1 450 Mathematics 06 Term I So fourth zero x = 0 x = Hence four zeroes will be, 0.
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